Question

A particle is under the action of two
forces Ę; = 4ỉ + 3ſ and Ěz = 3ỉ + 2ſ is
displaced from the position
(î+3j) to (4î+8j). The work done by the
process is-​

Answer 1

Explanation:

Here, r

1

=3i+2j−6k and r

2

=14i+13j+9k

So, displacement, (r

2

−r

1

)=(14i+13j+9k)(3i+2j−6k)

=11i+11j+15k

Hence, work done

=F.s

=(4i+j+3k).(11i+11j+15k)

=44+11+45=100J