Physics, asked by gunit7121, 11 months ago

A particle m charge and initial kinetic energy k is projecyed from infinity towards a heavy nucleus of charge q assumed to have fixed position how vlose will it comes to rest

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Answered by Anonymous
0
Initial kinetic energy =K

Initial potential energy =0

Therefore the total energy = K

When is come to rest instantaneously near the nucleous its total energy is in the form of potential energy =1/4πε Qq/r

Where r is the nearest distance of approach between the particle and heavy nucleous

K=1/4πε Qq/r 

or, 

r =1/4πε Qq/K


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