Question

A particle move 3m north then 4m east and final 6m south. Calculate distance and displacement???​

Answer 1

welcome to the concept of kinematics.

concept

distance: the length of actual path between initial and final position of a particle in a given interval of time is called distance covered by the particle.

displacement: shortest distance from the initial position to the final position of the particle is called displacement.

in this case observe the given fig.

distance=( 3+4+6)m= 13m

and displacement , shortest path between intial and final point = 5m .

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Answer 2

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$Heya$

Distance - 13m

Displacement - 5m

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