Physics, asked by madhu8212, 11 months ago

A particle move in x-y plane with a velocity v=2yi+4j. Equation of the path followed by the particle is

Answers

Answered by tesla369189
1

Answer:

r=2yt i + 4t j

Explanation:

r= x i + y j.

d r /dt= v.

So , r= integral (v dt)

We can integrate directly due to the continuity.

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