a particle move over three-quarters of a circle of radius r. what is the magnitude of its Displacement?
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Answer:
Explanation:
A particle moves over three quarters of a circle of radius r. What is the magnitude of its displacement?
Radius of circle =r
Body moves over 3 quarters
Magnitude of displacement = the hypotenuse of the 4th quarter whose Base and perpendicular r both = r unit.
Then,
(Hypotenuse)² = base² +perpendicular²
H² =r² +r²
H^2=2r²
H=√2r²
The magnitude of its displacement √2r²
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