A particle moves 10m in 4th seconds and 15m in 6th second of its motion . Calculate the distance travelled by in 7th second if the motion of the particleis uniformly accelerated .
Answers
Answered by
1
Bubut t y y uvu ycycycy vy
Answered by
2
Answer:
Explanation:
Given :
S4 = 10m ; S6 = 15m
Sn = u + a(n - 1/2)
⇒ u + a(4-1/2) = 10 ⇒ u+ 7a/2 = 10m ------ i
case ii = u + a(6 - 1/2) = 15 = u + 11a/2 = 15m ------ ii
On solving i and ii
we get a = 2.5 m/s² and u = 1.25m/s
Of S₇ = 1.25 + 2.5(7 - 0.5)
On simplification We Get
S₇ = 17.5 m
Similar questions