Question

A particle moves 3 meter north, the 4 metre east, and finally 6 m south. Calculate the distance and displacement traveled by the object

Pls answer

Answer 1

Answer:

As per the condition, the particle moves 3m in the east (x-direction),

4 m in the north ( y-direction) and

5 m due in the z-direction

(i) if the movement of the particle is to be speculated in the vectors term then it can be written as

R

=3i+4j+5k

ii) The question should find the displacement of the particle from the origin,

The net displacement will be =

(3²+4²+5²)

=

5

0

=7.07

The displacement is 7.07 units in the direction of vector 3i + 4j + 5k

Explanation:

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Answer 2

Explanation:

Distance = 3 + 4 + 6 = 13 m. Displacement is AB = under root 4 square + 3 square = 5m