Question

A particle moves 3m north, then 4m east, and then 12m vertically upwards, its displacement is

Answer 1

Distance:

(3+4+6)m = 13m

(Displacement)^2 =3^2+4^2

9+16 = 25

So,Displacement= 5m

Answer 2

Answer:

The displacement is 15.52 m

Explanation:

Given that,

A particle moves 3 m north, then 4 m east, and then 12 m vertically upwards as show in the figure

The displacement is the change in the position of the particle from initial position to final position.

According to figure,

The resultant displacement is defined as:

$D=\sqrt{(0-4)^2+(0-15)^{2}}$

$D = \sqrt{(-4)^2+(-15)^2}$

$D= \sqrt{241}$

$D = 15.52\ m$

Hence, The displacement is 15.52 m