Question

a particle moves along a circle of radius (20/π) with constant tangential acceleration . If the velocity of the particle is 80 m/s at the end of the second revolution after motion has began. What is the tangential acceleration?

Answer 1

Total distance travelled= 2πr× 2(for 2 revolution)

=S= 2×2π×20/π = 80m ...... (1)

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Now by using the formulae

v^2 - u^2 = 2aS

(80)^2 = 2a80 .(from 1)

a= 80×80/2×80 = 40m/s^2

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Answer 2

Answer:

• 40 rad/sec²

Explanation:

• Radius = 20/π m

• Velocity = 80 m/s

• Tangential Acceleration = ?

=> Angular velocity, ω = 80/π

=> ω = 4π

• ω0 = 0

=> (4π)² = 0+2α × 4π

=> α = 216π²/8π

=> α = 2π

• Tangential Acceleration = π.α = 2π . 20/π = 40 rad/s²

Hope it helps!

@charlie16