Question

A particle moves along a circle of radius R =1m so that its radius vector vecr relative to a point on its circumference rotates with the constant angular velocity omega=2rad//s. The linear speed of the particle is

Answer 1

Given :

Radius of circle (r) = 1m

Angular velocity (ω) = 2rad /sec

To find :

The linear speed of the particle

Solution :

• Angular velocity about center = 2× Angular velocity about any point on its circumference

• Angular velocity (ω) = 2(2) = 4 rad/sec

• Linear speed = r×ω

                     =1×4 = 4 rad/s

The linear speed of the particle is 4 rad/s