Physics, asked by gandhimaurya20, 15 hours ago

A particle moves along a semicircular path AB having diameter 2m. Calculate the distance and displacement of the particle from A to B​

Answers

Answered by 10an032
0

The distance and displacement produced by the particle is 44 m and 14 m.

Answered by bishal46151
0

Answer:

Distance=6.28m. Displacement=2m

Explanation:

semi perimeter of circle =2πr

=2π×1

=6.28

Displacement is shortest distance.so straight line is shortest line.Here diameter is straight line.so ans is 2m

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