A particle moves along a straight line between two points P and Q with constant acceleration
0.8 m s. Its velocity at Q is 1.2 m s1 greater than the velocity at P. If the distance PQ is 48
m, find the velocity at P. How long after passing P does it take the velocity to reach 48 m s-1
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Explanation:
ANSWER
8=
t
1
x
,12=
t
2
x
v
ˉ
=
t
1
+t
2
2x
=
8
x
+
12
x
2x
=
12+8
2×8×12
=9.6m/s
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