Question

a particle moves along a straight line such that it's displacement at any time is given by s=t^3-6t^2+3t+4 meters. the velocity when the acceleration is zero is​

Answer 1

Answer:

when a=0,t= 2s(after double differentiation of s)

putting t=2 in v=$\frac{ds}{dt}$

$3 {t}^{2} - 12t + 3 \\ v = 12 - 24 + 3 = - 9m/s$