Question

A particle moves along a straight line such that its displacement at any time t (in seconds) is given by s = (tº – 6t² + 4 + 4) metres. How many times does the particle make U-turn?​

Answer 1

Explanation:

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Answer 2

Answer:

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Explanation:

S=t 3 −6

2+3t+4

v=ds/dt

So =3t −12+3=v

again differentiate ,a= dt/dv

6t−12=0

t=2s

v=3(2) 2 −12×2+3=−9ms −1

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