Question

A particle moves along a straight line with a constant acceleration a =+0.5m/s^2.At t=0 it is at x=0 and its velocity is v=0.plot the velocity-time and position time graphs for the period t =0 to t=5 seconds

Answer 1

According to question the data which are given is a = 0.5 m/s2, u =0 at t =0 , 
hence at the end of 5 second the particle has some other velocity and it must have covered some distance or displacement (since the particle is going straight)
using equation of motion 
v = u+at
v = 0+0.5 x5 = 2.5 m/s.
now the displacement at the end of 5 second is 
s = ut +0.5 at2
s = 0+ 0.5 x  0.5 x 52
   = 6.25 metre..



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.çhere the two above figures shows the the velocity and position time graph.
now the equation is given 
x = 20+12t  
at t =0 x = 20m and at t = 5 x = 20+12x5 = 20+60 =80m
hence initial displacement is 20m 
and the slope = tanθ = x/t  = 60/5 = 12,.
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graphs are attached respectively

Answer 2

Answer:

We set the velocity function equal to zero and solve for t. ... At t = 0, we set x(0) = 0 = x0, since we are only interested in the ... Graph A is a plot of velocity in meters per second as a function of time ...