A particle moves along a straight line with a constant acceleration a= +0.5m/s square.At t=0 it is so x=0, and it's velocity is v =0. Plot the velocity-time and position-time graph for the period t=0 to t=5s
Answers
Answered by
4
According to question the data which are given is a = 0.5 m/s2, u =0 at t =0 ,
hence at the end of 5 second the particle has some other velocity and it must have covered some distance or displacement (since the particle is going straight)
using equation of motion
v = u+at
v = 0+0.5 x5 = 2.5 m/s.
now the displacement at the end of 5 second is
s = ut +0.5 at2
s = 0+ 0.5 x 0.5 x 52
= 6.25 metre..
.
.
.
.çhere the two above figures shows the the velocity and position time graph.
now the equation is given
x = 20+12t
at t =0 x = 20m and at t = 5 x = 20+12x5 = 20+60 =80m
hence initial displacement is 20m
and the slope = tanθ = x/t = 60/5 = 12,.
.
hence at the end of 5 second the particle has some other velocity and it must have covered some distance or displacement (since the particle is going straight)
using equation of motion
v = u+at
v = 0+0.5 x5 = 2.5 m/s.
now the displacement at the end of 5 second is
s = ut +0.5 at2
s = 0+ 0.5 x 0.5 x 52
= 6.25 metre..
.
.
.
.çhere the two above figures shows the the velocity and position time graph.
now the equation is given
x = 20+12t
at t =0 x = 20m and at t = 5 x = 20+12x5 = 20+60 =80m
hence initial displacement is 20m
and the slope = tanθ = x/t = 60/5 = 12,.
.
Similar questions