Question

A particle moves along a straight line with an acceleration described by the equation a = – 8s–2 where a is in m/s2 and s in m. When t = 1 s, s = 4 m and v = 2 m/s. Determine acceleration when t = 2 s​

Answer 1

Answer:

Solution

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a=dtdv=t2−1

on integration

v=t1+c

at t=1s v=1+c=3

c=2

at t=5s v=51+2=511m/s

m=11

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