Question

A particle moves along acircular path of radius R.The ratio of distance and magnitude of displacement of a particle on completing half revolution is​

Answer 1

Answer:

$\pi /2$

Explanation:

distance = 1/2 *circumference = 2$\pi$r *1/2 = $\pi r$

displacement = shortest route between start and end point = diameter = 2r

RATIO : distance/displacement

           = $\pi r/2r$

          =$\pi /2$

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