Question

A particle moves along the side ab BC cd of a square of 25 metres with a velocity of 15 metre per seconds its average velocity ​

Answer 1

Answer:

time taken by particle to cross any side = t

speed = d/t               (d is length of side)

t = 25/15 ..............1

now when particle moves from AB,BC,CD then it reaches to adjecent vertex D of square ...

total time taken = T = 3t =3(25/15) = 5sec

now average velocity = total displacement/total time

displacement BW initial poiny A & D is 25m so

average velocity  =  25/5 = 5m/s

option d is correct

Explanation:

Answer 2

total time = 25+25+25/15 = 5seconds

total displacement = 25m

Average velocity = total displacement/total time

= 25/5

= 5m/s