Question

A particle moves along the x-axis from x=0 to x=5m under the influence of a force given by, F=7-2x+3x2.

Calculate the work done. Please help!

Answer 1

Work done= integral F.Displacement
So, after integration u get
7x-x^2+x^3
Now substitute the values of x as5 and 0 respectively and subtract
U get 7*5-25+125-0
Ans= 135

Answer 2

Answer:

W = 135 joules

Explanation:

The force acting on the particle, $F=7-2x+3x^2$

We need to find the work done by the particle from x = 0 to x = 5 m. The integral form of work done is given by :

$W=\int\limits{F.dx}$

$W=\int\limits^5_0 {(7-2x+3x^2).dx}$

$W=7x-x^2+x^3|_0^5$

$W=7(5)-(5)^2+(5)^3$

W = 135 joules

So, the work done by the particle is 135 joules. Hence, this is the required solution.