Question

A particle moves along X-axis in such a way that its coordinate X varies with time t according to the equation x = (2-5t +6t^(2))m. The initial velocity of the particle is

Answer 1

Explanation:

Particle is moving along x-axis so displacement is also along x-axis

Now , ⇒ x = 6t²-5t+2

since , V = dx/dt

Differentiating w.r.t. 't'

⇒ v = 6 × 2t - 5

⇒ v = 12t - 5