Question

A particle moves from position P1= 3i^ + 2j^ - 6 k^ to position P2=14 i^ + 13 j^+ 9 k^ ,under the force of 4 i^ + j^ + 3 k ^then what will be the work done?​

Answer 1

Explanation:

Work done W = F • S dot product of force F and displacement S

Here W = ( 4I + I + 3k) • ( 11i + 11j + 15k)

= 44 +11+45 = 100 joule.