Question

a particle moves from the point (0,1) to the point (1,0) along a straight line as shown uf one of the forces acting on the paticle f=10N directed towards +X direction , the work done by f is equal to


​

Answer 1

Answer:

Explanation:

Force is given as    

F

=  

i

^

+5  

k

^

 

Displacement of the particle    

S

=(−3  

i

^

+4  

j

^

​  

+5  

k

^

)−(  

i

^

+3  

k

^

)= −4  

i

^

+4  

j

^

​  

+2  

k

^

 

Work done   W=  

F

.  

S

 

∴ W= (  

i

^

+5  

k

^

). (−4  

i

^

+4  

j

^

​  

+2  

k

^

)

⟹ W=(−4)(1)+(5)(2)=6 J

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