Question

A particle moves in a circle of radius 2 m with tangential acceleration 10 m/s². Then its angular
acceleration is​

Answer 1

Answer :-

• Angular acceleration ($\alpha$) = $\boxed{\textsf{\textbf{\red{5 \:rad/s²}}}}$

Given :-

• Tangential acceleration ($\sf{a_t}$) = 10 m/s²

• Radius (r) = 2 m

To find :-

• Angular acceleration ($\alpha$).

Formula used :-

• $\large{\boxed{\color{navy}{\sf{a_t = \alpha r}}}}$

Solution :-

${\sf{➪\:a_t = \alpha r}}$

${\sf{➪\:10 = \alpha \times 2}}$

${\sf{➪\:\alpha = \dfrac{\cancel{10}}{\cancel{2}} }}$

${\sf{➪\:\alpha = }}$ $\sf{\red{5\:rad/s²}}$