Question

A particle moves in a circle of radius R at constant angular speed Omega the maximum and minimum angular speed of the particle about the point in the plane circle at a distance 3R from the centre are respectively

Answer 1

Answer:

Hope the above attachment help you....

Answer 2

Allow the particle to go from point P to point Q.

In the diagram, the triangle is an isosceles triangle.

OP=OQ=R

Let ∠POQ=x

Using sine law:

sin( 2 180°−x​)

OP​= sinx PQ

​

sin2A=2sinAcosA ∴

PQ=2Rsin( 2 x​)=2Rsin( 2 θ​)

Explanation: