Question

A particle moves in a circle of radius R. The distance covered by the particle in 5
revolutions is
​

Answer 1

Answer:

For one revolution ,distance =circumference=2piR

For 5 revolution,distance=5*2piR=10piR

Then substitute pi(3.14or 22/7)

Answer 2

Answer:

The distance covered by the particle in 5 revolutions is 31.4R units.

Explanation:

Given a particle moves in a circle of radius R.

For one revolution, the distance covered by a particle in a circle of radius R will be the circumference of the circle.

The circumference of a circle is total length of its boundary.

The circumference of a circle is given by π times its diameter.

i.e., πd or 2πR.

So, for 1 revolution, the distance covered by a particle is 2πR

Thus for 5 revolutions, the distance covered by a particle is

$5\times 2\pi R=10\times3.14\times R=31.4 R\mbox{units}$

Therefore, the distance covered by the particle in 5 revolutions is 31.4R units.

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