If theta is an acute angle and cosec theta=root5then evaluate cot theta-cosec theta
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HEY.... USER...
here is ur answer ...
Theta is less than 90°
cosec theta=√5/1(h/p)
cot theta-cos theta
=(2/1-2/√5)
=(2√5-2/√5)
=so,2(√5-1)...
HOPE THIS WILL HELP U...
❤❤❤❤❤❤❤❤❤❤❤
HEY.... USER...
here is ur answer ...
Theta is less than 90°
cosec theta=√5/1(h/p)
cot theta-cos theta
=(2/1-2/√5)
=(2√5-2/√5)
=so,2(√5-1)...
HOPE THIS WILL HELP U...
❤❤❤❤❤❤❤❤❤❤❤
Answered by
3
hope it helps!!!!!!!
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