Question

A particle moves in a circle of radius R with a constant speed under a centripetal force F. The magnitude of work done in completing a full circle will be
(A) 2RF
(B) 2πRF
(C) πR²F
(D) Zero​

Answer 1

Answer:

Zero

Explanation:

The displacement for a full cyle is zero. Thus using the relation, work done =force×displacement or W=Fd

As displacement d=0 so W=0

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