Question

A particle moves in a circle of raduis 5 cm with a constant speed and time period 0.4π s .the speed of the particle is

Answer 1

Answer:

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Explanation:

The acceleration of the particle is 5\ m/s^2

The acceleration of the particle is 5\ m/s^2Explanation:

Time period T = 0.2\pi\ sec

Time period T = 0.2\pi\ secWe know that,

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocity

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radius

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time period

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formula

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}v=0.5\ m/s

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}v=0.5\ m/sNow,

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}v=0.5\ m/sNow,The acceleration is defined as

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}v=0.5\ m/sNow,The acceleration is defined asa =\dfrac{v^2}{r}

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}v=0.5\ m/sNow,The acceleration is defined asa =\dfrac{v^2}{r}Where, a = acceleration

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}v=0.5\ m/sNow,The acceleration is defined asa =\dfrac{v^2}{r}Where, a = accelerationv = velocity

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}v=0.5\ m/sNow,The acceleration is defined asa =\dfrac{v^2}{r}Where, a = accelerationv = velocityPut the value into the formula

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}v=0.5\ m/sNow,The acceleration is defined asa =\dfrac{v^2}{r}Where, a = accelerationv = velocityPut the value into the formulaa = \dfrac{0.5^2}{5\times10^{-2}}

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}v=0.5\ m/sNow,The acceleration is defined asa =\dfrac{v^2}{r}Where, a = accelerationv = velocityPut the value into the formulaa = \dfrac{0.5^2}{5\times10^{-2}}a = 5\ m/s^2

Time period T = 0.2\pi\ secWe know that,The velocity is defined as,v = \dfrac{2\pi r}{T}Where, v = velocityr = radiusT = time periodPut the value into the formulav = \dfrac{2\times3.14\times5\times10^{-2}}{0.2\times3.14}v=0.5\ m/sNow,The acceleration is defined asa =\dfrac{v^2}{r}Where, a = accelerationv = velocityPut the value into the formulaa = \dfrac{0.5^2}{5\times10^{-2}}a = 5\ m/s^2Hence, The acceleration of the particle is 5\ m/s^2