Question

 A particle moves in a circle with O as centre and OA= OB= 5 CM,,  as radius. It starts from A. Calculate (a)  the distance covered,  (b)  the displacement,  when it reaches B (take AB as diameter) ​

Answer 1

Answer:

(A). (Assuming that it goes from point A and return to point A by covering its circumference)

Circumference of a circle= 2πr ( where r is the radius)

= 2×22÷7×5

= 31.4285714

(B). ( Assuming that point B is on the opposite side of point A)

if A and B are on the opposite side, then the displacement =the diameter of the circle

diameter=AB=2r

AB= 2×OB

AB=2×5

AB=10

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Answer 2

$\green{\underline{\green{\underline{\pink{\bigstar{\blue{\mathbb{ANSWER}}}}}}}}$

Given AB is the diameter

Hence A and B must be 2 opposite points on the given circle

We know that

Distance = Total distance B/w 2 Points

Displacement=Shortest distance B/W 2 points

Therefore distance =2πr

• Distance =2(3.14)$\time$5
• Displacement= distance along AB =diameter

Displacement =2(5)=$\red{2cm}$

Distance =10$\times$3.14

distance=$\blue{31.4cm}$

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