Physics, asked by Shirin815, 1 year ago

A particle moves in a potential region given by U= 8x^ 2 - 4x + 400J. Its state of equilibrium will be

Answers

Answered by JunaidMirza
122
U = 8x^2 - 4x + 400
Differentiate with dx we will get F
F = 16x - 4

At equilibrium F = 0
0 = 16x - 4
x = 1/4 = 0.25 m

It’s state of equilibrium will be at x = 0.25 m
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