a particle moves in a straight line and its speed depends on time as v=|2t-3|. integration of vdt represents the distance travelled of the particle then find the displacement of the particle in 5sec
saurav01234567890:
Pls report my ans by mistake i submitted the half answer
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Answered by
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The function given in your question is an absolute function and hence to integrate it , the function has to be splited into two parts in the limit range.
First part - For which the value offunction is negative which in our case in the range 0 to 3/2 , but we know displacement is never negative , therefore we neglect the range of the limit
Second part - For which value of function is positive which in our case is 3/2 to 5
Now, performing the required integration we have,
x =
Answered by
0
Answer:
14.5 metres
Explanation:
see the attached document
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