Question

A particle moves in a straight line in such a way that it's velocity after t seconds is (2t + 5)m/s. Find the distance travelled in the first 4 seconds.

Answer 1

Answer:

36m

Step-by-step explanation:

To find displacement, and in this case, the distance travelled, integrate the velocity

∫(2t +5) dt = 2t^2 + 5t

Sub t = 4,

[2(4)]^2 + t(4) = 36m