Question

A particle moves in a straight line in such a way that its velocity at any time is given by v = 3t + 2, where t is time in seconds. The acceleration at t = 1 second is : (A) 3 m/s2 (B) 15 m/s2 (C) 5 m/s2 (D) 2 m/s2​

Answer 1

GIVEN:

The equation of the velocity at any time is 3t + 2.

To Find:

We have to find the acceleration of the body at time 1sec.

Solution:

As we know we can find the acceleration of the body by differentiating the equation of velocity equation of the particle with respect to the time.

here, V = 3t + 2

As, a = dv

            dt

so, after differentiating the equation you will get the result as 3.

As we know three is a constant and there is no value arbitrary value on it to put on.

so, this shows that the particle is in an uniform acceleration of 3m/$s^{2}$.

FINAL RESULT: 3m/$s^{2}$