Question

A particle moves in a straight line so that distance s= √t where t is time, then it's acceleration is proportional to

Answer 1

⭐《ANSWER》

$\huge\mathfrak{\underline {\underline\pink {ANSWER}}}$

↪Actually welcome to the concept of the KINEMATICS AS APPROACH OF DERIVATIVES

↪since we know that ,

↪X = displacement

↪thus, dx/dt = Velocity

↪and now , dv/dt = ACCELRATION

↪, thus the double derivative of the displacement will the accelration, so we get as

↪S = root t

↪so , ds/dt = V = 1/2 root t

↪and now , dV/dt = d/dt ( 1/2 root t)= acceleration

〽so here , a = -1/4 * t^-3/2

↪so here , acceleration is proportional to " t ^-3/2 "