Question

A particle moves in a straight line. the distance s (measured in metres) are covered by the particle in time t (in second) is given by s= 2t^2 +5t -4. find the velocity and acceleration of the particle in 6 seconds.​

Answer 1

Step-by-step explanation:

Given distance S = 2t²+5t -4

We have to find velocity at 6 sec

as we know that V = ds/dt

hence, Diffrentiate " S" distance with respect to time

∵ S = 2t²+ 5t - 4

we get , V = 4t +5

so ,we have to find velocity at 6 sec

V = 4t + 5

V = 4*6 + 5 = 29m/s

We also know that , a = dv/dt

so, Diffrentiate " V" velocity with respect to t

∵ V = 4t + 5

a = dv/dt = 4m/s² Answer .

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