A particle moves in a straight line with a velocity 8 ms−1 for 2 seconds and then with a velocity 10 ms−1 for 5 seconds. Find the average velocity during this time interval?
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Answer:
9.43 m/s
Explanation:
during the first interval,
v = 8 m/s
t = 2 s
=> s = vt = 16 m
during the second interval,
v = 10 m/s
t = 5 s
s = vt = 50 m
average speed = total distance / total time = 50+16 / 5+2 = 66/7 = 9.428 m/s
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