A particle moves in a straight line with initial velocity 4 m/s and a constant acceleration of 6 m/s2 . Find the average velocity of the particle in a time interval from :
(a) t = 0 to t =2
(b) t = 2s to t = 4s
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Answered by
0
Answer:
average velocity is 25m/s so distance will be 25×20=500m
now finding area of the graph between velocity and time graph we get
area of two triangles + area of rectangle.
2.
2
1
t.5.t+(25−2t).5t=500=>t
2
−25t+100
=>t=5
so option B is answer.
Answered by
1
Explanation:
lost and found..
the essay you have written is it full or half
I mean is it correct?
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