Question

A particle moves in x-y plane, starting from A, along straight line paths AB and then BC, as shown in the
graph. When it is at point P, angle between directions of its initial velocity and instantaneous velocity is:



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Answer 1

Given:

Angle of line BC with x axis = 45°

To find:

Angle between directions of initial velocity and instantaneous velocity at point P.

Solution:

Let the point of origin be O

Angle BAO = 37°

When the line AB in extended downwards, it also makes 37° angle with the x axis.

The initial velocity direction will be along the line AB

The instantaneous velocity will be in the direction of BC

The total angle = 37° + 45°

= 82°

Therefore, the angle between the direction of initial velocity and instantaneous velocity is 82°.

Answer 2

82..

explanation as attachment