A particle moves in X-Y plane under the influence of a force such that the linear momentum it possess is
p(t)= A[icos(kt)-jcos(kt)]
where A and k are constants. The angle between the force and momentum is?
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F(t) = kA[- icos(kt) + jcos(kt)]
taking dot product of force and momentum
F(t).P(t) = zero
F(t)P(t)sinФ = 0
sinФ = sin0
Ф= 0
taking dot product of force and momentum
F(t).P(t) = zero
F(t)P(t)sinФ = 0
sinФ = sin0
Ф= 0
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