a particle moves in xy plane with constant acceleration a directed along the negative y-axis
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Comparing the eq. with projectile from earth=>y=x.tan m -x^2tan m/R...where R=Range
We get a=g...b=tan m.....c=tan m/R
hence c=b/R=>R=b/c
But R=u^2sin 2m / a
Hence u^2=ab/2c(sin m).(cos m)
as tan m=b,putting the value of sin m and cos m
the eq becomes
u^2=a(1+b^2)/2c
Hence u=root[a(1+b^2)/2c]
ANS.
Regards.
We get a=g...b=tan m.....c=tan m/R
hence c=b/R=>R=b/c
But R=u^2sin 2m / a
Hence u^2=ab/2c(sin m).(cos m)
as tan m=b,putting the value of sin m and cos m
the eq becomes
u^2=a(1+b^2)/2c
Hence u=root[a(1+b^2)/2c]
ANS.
Regards.
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