Question

A particle moves on a circular path of radius 0.2 m with an angular acceleration
0.25 rad/s. The particle starts from rest, find the time at which the magnitude of
radial acceleration and the magnitude of tangential acceleration are same.
a. 15
b. 2 s
c. 35
d. 4 s​

Answer 1

Answer:

,

As we realize that

Centripetal speeding up = v^2/r

To start with condition of movement

ω = ωo+ αt

As beginning rakish speed is 0

ω = αt

v/r = 4t

v = 4tr.

Extraneous increasing speed = centripetal quickening

αr = a

4r = v^2/r

4r = (4tr)2/r

4 = 16t^2

t = ½

t = 0.5 sec.