Question

A particle moves on a circular path of radius r.it complete one revolution in 40s. calculate distance & displacement in 2min 20s.

Answer 1

❇❇❇ hey there,,,,
here is ur answer

➖➖ , given: time period for one revolution is 40s

, calculate for 2 min 20s ➡. 140s

distance = 2πr for 40 second

then for 140 second

➡➡ total revolutions will be = 140÷40 = 3.5


s= 2πr×3.5

s= 7πr is the distance

✔✔✔displacement ➖➖
✴✴ since for one. complete. revolution the DISPLACEMENT is zero, hence we can just calculate for last 20 seconds

it becomes

, ⏩⏩ s = 2πr÷2

s= π ×r

since this time period is exactly half of the value of the given value, hence the DISPLACEMENT will also be half, ...

❕❕hope it helps u❗❗❗

Answer 2

Radius of the circular path = R

Time= 2min 20sec = 140seconds

Distance covered in One second= 2π R

Time for one Revolution = 40 seconds

Revolution completed in 140 sec= 140/40
= 3.5 second

Distance covered in 3.5 second = 3.5× 2πR
= 7π R

Displacement in 3.5 revolution = 2R
(shortest distance between initial and final distance)

Ratio of displacement to distance
=2π/7π
= 2/7

Hope this helps you....
HAVE A BEAUTIFUL DAY!