a particle moves on a track of a square field of side 6 metre and complete 3.5 round calculate its distance and displacement
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Answered by
1
Answer:
In one complete cycle, it comes back to its initial position, so the displacement of the object is zero.
Distance travelled = circumference of the circle = 2πr
=2×
7
22
×3.5
=22m
Answered by
0
Answer:
for one round distance=6×4=24
for 3.5 rounds distance=24×3.5= 84
displacement=length of diagonal of square= 6(2)^1/2= 6root2 = displacement
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