Question

a particle moves over the sides of an equilateral triangle with constant speed v. find the magnitude of average acceleration?

Answer 1

In case of a constant speed, the acceleration will always be zero. But in this case, The particle moves in a clockwise direction from A to B then B to C, covering equal distance (l) in each case.

Therefore, the magnitude of average acceleration will be = ( total displacement / time taken )

= ( 2l / v ) =( √3/2) & ( v 2 /a ).