Question

A particle moves over three quarters of a circle of radius R what is the magnitude of its displacement​

Answer 1

Answer:

The answer is 2root r units.

Explanation:

When the particle moves three quarters of the circle,

The displacement between center and starting point is r,

The displacement  between center and finishing point is r,

The displacement between the starting point and ending point is v(r^2+r^2)

                                                       = v2r^2 = rv2

Hope this helps you.

Answer 2

Explanation:

i hope this would make you understand it properly.

1/4= quarter.

so 3/4 of circle given in the figure.

ab displacement because its the shortest length between two points. so ab would be the displacement. otherwise if distance would have been asked in question we would have calculated circumference.