Question

a particle moves over three quarters of a circle of radius r. What is the magnitude of its displacement.​

Answer 1

Answer:

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Answer 2

Total distance = 2πr

The distance covered by the particles =(2πr*3/4)

                                                               = 3πr/2

As it is a circular way so, we can calculate it in two method either by using Pythagorean triplate or by subtracting fro the perimeter. Subtraction from the perimeter is easier though not so much used but less completed. Its doing by subtracting from the perimeter and it should subtracted to get the displacement as it is a circle and whenever it will complete one complete round then the displacement will be 0 and to get he displacement we should always have to subtracted the distanced value from the perimeter.

So, the displacement is_

(2πr)-(3πr/2)

=(4πr-3πr)/2

=πr/2

So, the displacement of the particle is πr/2