A particle moves through 3m due east 4m due north and finally 5m vertically upward
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Answered by
23
So,
As per the condition the particle moves 3m in the x direction,
4m due in the positive y direction and 5m due in z direction
So, if the movement of the particle is to be speculated in the vectors term then it can be written as
3i+ 4j +5k
So,
The question should be find the displacement of the particle from the origin,
So,
The net displacement will be
=√(3² + 4² +5²)
=√50
=7.07
The displacement is 7.07 units in the direction of vector 3i + 4j + 5k
As per the condition the particle moves 3m in the x direction,
4m due in the positive y direction and 5m due in z direction
So, if the movement of the particle is to be speculated in the vectors term then it can be written as
3i+ 4j +5k
So,
The question should be find the displacement of the particle from the origin,
So,
The net displacement will be
=√(3² + 4² +5²)
=√50
=7.07
The displacement is 7.07 units in the direction of vector 3i + 4j + 5k
JinKazama1:
|s| = √50 units
Answered by
3
Answer:
As per the condition, the particle moves 3m in the east (x-direction),
4 m in the north ( y-direction) and
5 m due in the z-direction
(i) if the movement of the particle is to be speculated in the vectors term then it can be written as
R =3i+4j+5k
ii) The question should find the displacement of the particle from the origin,
The net displacement will be = (3²+4²+5²) ⇒
=7.07
The displacement is 7.07 units in the direction of vector 3i + 4j + 5k
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