Physics, asked by hamzakhan9217, 1 year ago

A particle moves through 3m due east 4m due north and finally 5m vertically upward

Answers

Answered by NavaN11
23
So,

As per the condition the particle moves 3m in the x direction,

4m due in the positive y direction and 5m due in z direction

So, if the movement of the particle is to be speculated in the vectors term then it can be written as

3i+ 4j +5k

So,

The question should be find the displacement of the particle from the origin,

So,

The net displacement will be

=√(3² + 4² +5²)

=√50

=7.07

The displacement is 7.07 units in the direction of vector 3i + 4j + 5k

JinKazama1: |s| = √50 units
NavaN11: Thanx man,
Answered by ARKRANGER
3

Answer:

As per the condition, the particle moves 3m in the east (x-direction),

4 m in the north ( y-direction) and  

5 m due in the z-direction  

(i) if the movement of the particle is to be speculated in the vectors term then it can be written as

R =3i+4j+5k

ii) The question should find the displacement of the particle from the origin,

The net displacement will be =  (3²+4²+5²)                                                      ​   ⇒\sqrt{50}

=7.07

The displacement is 7.07 units in the direction of vector 3i + 4j + 5k

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