Question

PQRS is a rectangle in which PQ=20cm and QR=10cm a semicircle is drawn with centre O and radius 10root 2cm.it passed through A and B . Find area of te shaded region

Answer 1

According to question

Length of rectangle  L = 20 Cm

Breadth of rectangle  B = 10 Cm

Thus Area of rectangle PQRS = L *  B 
                                                 = 20 * 10
                                                  = 200 Cm^2

Radius of semicircle   r = 10 root 2 Cm

Thus Area of semicircle  = 1/2 pi R^2
                                        = 1/2 * 22/7 * 100 * 2
                                       = 314
so Area of shaded region = 314 - 200
                                         = 114 Cm^2

Answer 2

Answer:43

Step-by-step explanation:

Draw OX parallel to PQ

In the right triangle: sin(theta)=10/10√2

=1/√2

Therefore theta is 45°

Then area of segment=area of sector-area of triangle

=50(3.14)-20

=157-20

=137

Then area of shaded region=area of rectangle-area of segment

=200-137

=43