find f(3√2) if f(x)= x²-3√2 x-1
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just make 3root2 into root18 and put in eqaution
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Given f(x)=x^2-3×2^(1/2) x-1
Then f (3× 2(1/2) )= ?
F (3 × root2)=[(3×root2)^2 - (3×root2)(3×root)-1]
=(18-18-1)
=-1
Then f (3× 2(1/2) )= ?
F (3 × root2)=[(3×root2)^2 - (3×root2)(3×root)-1]
=(18-18-1)
=-1
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